P Xxvii 2014 10a ((full)) -

$$ \text{Volume Ratio} = k^3 = \left(\frac{2}{3}\right)^3 $$

Substitute the values: $$ \frac{326}{V_B} = \frac{8}{27} $$ p xxvii 2014 10a

We know the volume of Jug A ($V_A$) is typically given as in this specific paper. We need to find $V_B$. $$ \text{Volume Ratio} = k^3 = \left(\frac{2}{3}\right)^3 $$

Let the Volume of Jug A be $V_A$ and Volume of Jug B be $V_B$. $$ \frac{V_A}{V_B} = \frac{8}{27} $$ p xxvii 2014 10a